ΔABC is right angle at B. If m∠C = 45°. Then find the value of (cosecA - $$\sqrt 3 $$ ) =?
A. $$\frac{{4 - \sqrt 3 }}{2}$$
B. $$\sqrt 2 - \sqrt 3 $$
C. $$ - \frac{{\sqrt 3 }}{2}$$
D. $$\frac{{\sqrt 6 - 1}}{{\sqrt 3 }}$$
Answer: Option B
Solution (By Examveda Team)
$$\eqalign{ & {\text{cosec}}A - \sqrt 3 \cr & = \frac{{\sqrt 2 x}}{x} - \sqrt 3 \cr & = \sqrt 2 - \sqrt 3 \cr} $$
This Question Belongs to Arithmetic Ability >> Circular Measurement Of Angle
Related Questions on Circular Measurement of Angle
If 0 ≤ θ ≤ $$\frac{\pi }{2}$$ and sec2θ + tan2θ = 7, then θ is
A. $$\frac{{5\pi }}{{12}}$$ radian
B. $$\frac{\pi }{3}$$ radian
C. $$\frac{\pi }{6}$$ radian
D. $$\frac{\pi }{2}$$ radian
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