ΔABC is right angled at B. If m∠A = 60° then find the value of (secC + 2).
A. $$\frac{{2 + 2\sqrt 3 }}{{\sqrt 2 }}$$
B. $$\frac{4}{3}$$
C. $$\frac{{2 + 2\sqrt 3 }}{{\sqrt 3 }}$$
D. $$\frac{3}{4}$$
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & \sec C + 2 \cr & \frac{{2x}}{{\sqrt 3 x}} + 2 \cr} $$
$$\eqalign{ & \frac{2}{{\sqrt 3 }} + 2 \cr & \frac{{2 + 2\sqrt 3 }}{{\sqrt 3 }} \cr} $$
This Question Belongs to Arithmetic Ability >> Circular Measurement Of Angle
Related Questions on Circular Measurement of Angle
If 0 ≤ θ ≤ $$\frac{\pi }{2}$$ and sec2θ + tan2θ = 7, then θ is
A. $$\frac{{5\pi }}{{12}}$$ radian
B. $$\frac{\pi }{3}$$ radian
C. $$\frac{\pi }{6}$$ radian
D. $$\frac{\pi }{2}$$ radian
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