Two 0.68 µF capacitors are connected in series across a 10 kHz sine wave signal source. The total capacitive reactance is

A. 46.8 Ω

B. 4.68 Ω

C. 23.41 Ω

D. 11.70 Ω

Answer: Option A

Solution(By Examveda Team)

Capacitive Reactance should be:
$${{\text{X}}_{\text{C}}} = \frac{1}{2}\pi {\text{fC}}$$
Where:
f = frequency
C = Capacitance
For capacitors in series:
$$\eqalign{ & \frac{1}{{\text{C}}} = \frac{1}{{{{\text{C}}_1}}} + \frac{1}{{{{\text{C}}_2}}} \cr & {\text{So,}}\,{\text{C}} = 3.4 \times {10^{ - 7}}{\text{F}} \cr & {\text{So:}} \cr & {{\text{X}}_{\text{C}}} = \frac{1}{{2\pi \cdot 3.4 \times {{10}^{ - 7}} \cdot 10000}} = 46.8\Omega \cr} $$