Two chords AB and CD of a circle with centre O intersect at P. If ∠APC = 40°. Then the value of ∠AOC + ∠BOD is
A. 50°
B. 60°
C. 80°
D. 120°
Answer: Option C
Solution (By Examveda Team)

x + y = 40°
2x + 2y = 80°
∠AOC + ∠BOD = 80°
A. 50°
B. 60°
C. 80°
D. 120°
Answer: Option C
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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