Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If ∠BDC = 120°, then the value of ∠ABP is equal to
A. 60°
B. 80°
C. 100°
D. 120°
Answer: Option A
Solution (By Examveda Team)
According to questionGiven:
∠BDC = 120°, ∠ABP =?
∴ ∠CDP = 180° - ∠BDC
∠CDP = 180° - 120°
∠CDP = 60°
CD || AB
∴ ∠CDP = ∠ABP = 60°
This Question Belongs to Arithmetic Ability >> Geometry
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In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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