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Two circles of radius 13 cm and 15 cm intersect each other at points A and B. If the length of the common chord is 24 cm, then what is the distance between their centres?
Answer & Solution
Correct Answer:
Option
D
In ΔADO
OD = $$\sqrt {{{\left( {15} \right)}^2} - {{\left( {12} \right)}^2}} $$ = 9 cm
In ΔADC
DC = $$\sqrt {{{\left( {13} \right)}^2} - {{\left( {12} \right)}^2}} $$ = 5 cm
or use Triplet
5, 12, 13 and 9, 12, 15
∴ OC = DC + OD = 5 + 9 = 14 cm
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