Two circles touch each other externally at T. RS is a direct common tangent to the two circles touching the circles at P and Q. ∠TPQ = 42°. ∠PQT (in degrees) is:
A. 48
B. 45
C. 42
D. 60
Answer: Option A
Solution(By Examveda Team)

In ΔPTQ
∠QPT + ∠PTQ + ∠PQT = 180°
42° + 90° + ∠PQT = 180°
∠PQT = 180° - 132°
∠PQT = 48°
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