Two concentric circles are of redii 13 cm and 5 cm. The length of the chord of the larger circle which touches the smaller circle is:
A. 24 cm
B. 15 cm
C. 13 cm
D. 10 cm
Answer: Option A
Solution(By Examveda Team)
AM = 12
AB = 2 × 12 = 24 cm
A. 24 cm
B. 15 cm
C. 13 cm
D. 10 cm
Answer: Option A
A. 1 : 2
B. 1 : 3
C. 1 : √3
D. 1 : √2
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
A. 80°
B. 40°
C. 90°
D. 50°
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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