Two helical springs of the same material and of equal circular cross-section, length and number of turns, but having radii 80 mm and 40 mm, kept concentrically (smaller radius spring within the larger radius spring), are compressed between two parallel planes with a load W. The inner spring will carry a load equal to
A. $$\frac{{\text{W}}}{2}$$
B. $$\frac{{2{\text{W}}}}{3}$$
C. $$\frac{{\text{W}}}{9}$$
D. $$\frac{{8{\text{W}}}}{9}$$
Answer: Option B
This Question Belongs to Mechanical Engineering >> Machine Design
D. 8W/9
load is inversely proprotion to cube of radius. this way ratio of load shared by outer to inner spring is (1:8).so inner spring carry load (8/9W)