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Two infinite parallel plates 10 mm apart have maintained between them a potential difference of 100 V. The acceleration of an electron placed between them is

A. 0.56 x 1015 m/s2

B. 1.5 x 1015 m/s2

C. 1.6 x 1015 m/s2

D. 1.76 x 1015 m/s2

Answer: Option D


This Question Belongs to Electrical Engineering >> Electrostatics

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Comments ( 2 )

  1. SUBHASMITA DEY
    SUBHASMITA DEY :
    2 years ago

    Given, V=100v
    d=10mm=0.01m
    E= V/d =100 /0.01 =10000 v/m
    F=qE =(1.6*10^-19 )(10^4) as here q = charge of e-s
    F=1.6*10^-15
    m *a =1.6*10^-15
    a =(1.6*10^-15)/(9.1*10^-31) m=mass of e-s
    a= 1.76 * 10^15

  2. Sajida Hamayun
    Sajida Hamayun :
    3 years ago

    Explanation?

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