Two infinite parallel plates 10 mm apart have maintained between them a potential difference of 100 V. The acceleration of an electron placed between them is

Solution (By Examveda Team)

First, let's understand the key concepts:

* Electric Field (E): This is the force exerted on a charge due to the voltage difference.
* Force on an Electron (F): An electron experiences a force in an electric field.
* Acceleration (a): This is the rate of change of velocity caused by the force.

Here's how to solve the problem step-by-step:

1. Find the Electric Field (E):
* The electric field between two parallel plates is uniform and calculated as E = V/d,
* where V is the potential difference (100 V) and d is the distance between the plates (10 mm = 0.01 m).
* So, E = 100 V / 0.01 m = 10000 V/m.

2. Find the Force on the Electron (F):
* The force on an electron in an electric field is F = qE,
* where q is the charge of an electron (approximately 1.602 x 10^-19 Coulombs).
* So, F = (1.602 x 10^-19 C) * (10000 V/m) = 1.602 x 10^-15 N.

3. Find the Acceleration (a):
* Using Newton's second law, F = ma, where m is the mass of the electron (approximately 9.109 x 10^-31 kg).
* So, a = F/m = (1.602 x 10^-15 N) / (9.109 x 10^-31 kg) ≈ 1.76 x 10¹⁵ m/s².

Therefore, the correct answer is:

Option D: 1.76 x 10¹⁵ m/s²