Two infinite parallel plates 10 mm apart have maintained between them a potential difference of 100 V. The acceleration of an electron placed between them is
A. 0.56 x 1015 m/s2
B. 1.5 x 1015 m/s2
C. 1.6 x 1015 m/s2
D. 1.76 x 1015 m/s2
Answer: Option D
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Given, V=100v
d=10mm=0.01m
E= V/d =100 /0.01 =10000 v/m
F=qE =(1.6*10^-19 )(10^4) as here q = charge of e-s
F=1.6*10^-15
m *a =1.6*10^-15
a =(1.6*10^-15)/(9.1*10^-31) m=mass of e-s
a= 1.76 * 10^15
Explanation?