Two pipes can fill an empty tank separately in 24 minutes and 40 minutes respectively and a third pipe can empty 30 gallons of water per minute. If all the three pipes are open, empty tank becomes full in one hour. The capacity of the tank (in gallons) is?
A. 500
B. 550
C. 600
D. 700
Solution (By Examveda Team)
Work Efficiency of Pipe One = 100/24 = 4.16% per minute
Work Efficiency of Pipe two = 100/40 = 2.5% %per minute.
Work Efficiency of third pipe which is doing a negative work = 30 gallons per minute
All three pipes can fill empty tank in 60 minute.
Work efficiency together = 100/60 = 1.66% per minute
Work Efficincy of third pipe = (1.66 - (4.16 +2.5)) = - 5 (-ve sign denottes, it is doing negative work.)
So,
5 = 30 gallons
1% = 30/5
Thus, 100% = (30*100)/5
So, Capicity of the tank = 600 gallons.
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Efficiency of inlet pipe A and B
24A= 40B
A:B= 5:3
TOTAL WORK UNIT IS= 24*5=120
LET EFFICIENCY OF OUT LET PIPE C IS = x
Atq
(5+3-x)60= 120
480-60x= 120
60x= 360
X= 6
So outlet Pipe c 's empty time =120/6= 20 minutes
So total capacity of the tank is= 20*30=600 litter
Solved by
ABU SAYED IMRAN
MGT17 (RU)BD
Suppose x Gallon( xg ) of water can be hold by tank
then
Suppose first pipe can fill tank in 1 minute = x/24
Similarly, Second pipe in 1 minute= x/40
We are given that third pipe can empty in 30g/min
Also, All three pipe together can fill in 1hr i.e. 60min
and in 1min all pipe fills x/60 gallon of water
According to problem
x/24 + x/40 + 30=x/60
x/24 +x/40 - x/60= 30
12x=30*240
we get x=600 i.e. 600gallon
My Solution is 1/24+1/40-1/x= 1/60; from this 1/x= 1/20; that means whole tank can empty in 20 Minutes. 1 minute--------> 30 Gallons; 20--------> ? gallons...
20 minutes is 20*30= 600 Gallons.. simple way.............like it if u understands it...
I think no need to do like examveda
1/24 + 1/40 - 1/x = 1/60 ( x = minutes need to empty)
1/x = 1/20
it means 20 minutes need to empty the tank
So total capacity of tank (20*30) = 600 gallons
Wrong....... TEAM EXAMVEDA...............
Where?
Got That. Edited Now! Thank You!
@Leelanand, Please use to post options as well if possible.