Two series capacitors (one 2 µF, the other of unknown value) are charged from a 24 V source. The 2 µF capacitor is charged to 16 V and the other to 8 V. The value of the unknown capacitor is
A. 1 µF
B. 2 µF
C. 4 µF
D. 8 µF
Answer: Option C
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Current is same in series circuit. Here two capacitors r in series, so charge of each capacitor is also same.
The charge of 1st Cap. is; Q = C1 x V1 = 2 x 10^-6 x 16 = 32 microF.
From this Therefore, second Cap.; C2 = Q/V2 = (32 x 10^-6)/8 = 4 microF.