U238 will undergo fission by
A. High energy (fast) neutrons alone
B. Low energy (slow) neutrons alone
C. Either fast or slow neutrons
D. Medium energy neutrons
Answer: Option A
Solution(By Examveda Team)
U238 will undergo fission by high energy (fast) neutrons alone.The much more abundant uranium-238 does not undergo fission and therefore cannot be used as a fuel for nuclear reactors. However, if uranium-238 is bombarded with neutrons it absorbs a neutron and is transformed into uranium-239.
This Question Belongs to Mechanical Engineering >> Power Plant Engineering
Related Questions on Power Plant Engineering
Reactors for propulsion applications use
A. Natural uranium
B. Molten lead
C. Any form of uranium
D. Thorium
Reactors designed for propulsion applications are designed for
A. Natural uranium
B. Enriched uranium
C. Pure uranium
D. Any type of uranium
Reactors for propulsion applications are designed for
A. Any form of uranium
B. Natural uranium
C. Enriched uranium
D. Plutonium
The size of the reactor is said to be critical when
A. Chain reaction can be initiated
B. It becomes uncontrollable
C. It explodes
D. It produces no power
Join The Discussion