Under Binomial distribution standard deviation ($$\sigma $$) can be computed by
A. $$\sigma = \frac{{\sqrt {npq} \left( {1 - p} \right) \times 100}}{2}$$
B. $$\sigma = \frac{{n + 1 - p}}{n}$$
C. $$\sigma = \sqrt {npq} $$
D. $$\sigma = \frac{{n + p}}{n}$$
Answer: Option C
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