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Under Binomial distribution standard deviation ($$\sigma $$) can be computed by

A. $$\sigma = \frac{{\sqrt {npq} \left( {1 - p} \right) \times 100}}{2}$$

B. $$\sigma = \frac{{n + 1 - p}}{n}$$

C. $$\sigma = \sqrt {npq} $$

D. $$\sigma = \frac{{n + p}}{n}$$

Answer: Option C


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