What does the following piece of code do?
for (int i = 0; i < arr.length-1; i++)
{
for (int j = i+1; j < arr.length; j++)
{
if( (arr[i].equals(arr[j])) && (i != j) )
{
System.out.println(arr[i]);
}
}
}
for (int i = 0; i < arr.length-1; i++)
{
for (int j = i+1; j < arr.length; j++)
{
if( (arr[i].equals(arr[j])) && (i != j) )
{
System.out.println(arr[i]);
}
}
}A. Print the duplicate elements in the array
B. Print the element with maximum frequency
C. Print the unique elements in the array
D. Prints the element with minimum frequnecy
Answer: Option A
Related Questions on Searching Algorithms
A. Jump Search
B. Linear Search
C. Interpolation Search
D. Binary Search
What is the time complexity of binary search on a sorted array?
A. O(n log n)
B. O(n)
C. O(n2)
D. O(log n)
What is the time complexity of binary search in a balanced binary search tree (BST)?
A. O(log n)
B. O(n)
C. O(n log n)
D. O(1)
Which searching algorithm is most efficient for large datasets that are sorted?
A. Jump Search
B. Interpolation Search
C. Linear Search
D. Binary Search

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