What happens in a reversible adiabatic expansion process?

A. Heating takes place

B. Cooling takes place

C. Pressure is constant

D. Temperature is constant

Answer: Option B

Solution(By Examveda Team)

Since for an adiabatic process \[T{V^{\gamma - 1}} = {\rm{CONSTANT}}\]     and on integration of this equation we get \[ln\left( {\frac{{{T_2}}}{{{T_1}}}} \right) = - \left( {\left( {\gamma - 1} \right)ln\frac{{{V_2}}}{{{V_1}}}} \right)\]       since for expansion process \[{V_2} > {V_1}\]   Hence \[ \Rightarrow {T_2} < T_1\]
So, cooling takes place.