What happens in a reversible adiabatic expansion process?
A. Heating takes place
B. Cooling takes place
C. Pressure is constant
D. Temperature is constant
Answer: Option B
Solution (By Examveda Team)
Since for an adiabatic process \[T{V^{\gamma - 1}} = {\rm{CONSTANT}}\] and on integration of this equation we get \[ln\left( {\frac{{{T_2}}}{{{T_1}}}} \right) = - \left( {\left( {\gamma - 1} \right)ln\frac{{{V_2}}}{{{V_1}}}} \right)\] since for expansion process \[{V_2} > {V_1}\] Hence \[ \Rightarrow {T_2} < T_1\]So, cooling takes place.
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
Join The Discussion