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What is output of the following code:
public class Test{
        public static void main(String[] args){
                int[] x = {120, 200, 016 };
                for(int i = 0; i < x.length; i++)
                        System.out.print(x[i] + " ");
        }
}

A. 120 200 16

B. 120 200 14

C. 120 200 016

D. 016 is a compile error. It should be written as 16.

Answer: Option B

Solution(By Examveda Team)

016 is an octal number. The prefix 0 indicates that a number is in octal.


This Question Belongs to Java Program >> Array

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Comments ( 3 )

  1. Shamsul Haque
    Shamsul Haque :
    6 years ago

    @Abhichek Tiwari,
    In the value 016, 0 is representing that the whole no.(016) is Octal no. not an integer so the compiler will convert it into its corresponding integer value which is:
    0*8^2+1*8^1+6*8^0=14

  2. Rajya Lakshmi282
    Rajya Lakshmi282 :
    7 years ago

    here we are converting into octal.
    0*8^2+1*8^1+6*8^0=14

  3. Abhishek Tiwari
    Abhishek Tiwari :
    8 years ago

    if 0 is octal then the value will remain 16 how it will change to 14

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