What is the output for the below code?
class A{
private void printName(){
System.out.println("Value-A");
}
}
class B extends A{
public void printName(){
System.out.println("Name-B");
}
}
public class Test{
public static void main (String[] args){
B b = new B();
b.printName();
}
}
class A{
private void printName(){
System.out.println("Value-A");
}
}
class B extends A{
public void printName(){
System.out.println("Name-B");
}
}
public class Test{
public static void main (String[] args){
B b = new B();
b.printName();
}
}A. Value-A
B. Name-B
C. Value-A Name-B
D. Compilation fails - private methods can't be override
E. None of these
Answer: Option B
Solution(By Examveda Team)
You can not override private method , private method is not availabe in subclass . In this case printName() method a class A is not overriding by the printName() method of class B. printName() method of class B is a different method. So you can call printName() method of class B.
This Question Belongs to Java Program >> Inheritence
A. The process of acquiring properties and behaviors of one class by another
B. The process of creating objects
C. The process of encapsulation
D. The process of overloading methods
In Java, which keyword is used to implement inheritance between classes?
A. inheritsFrom
B. inherits
C. implements
D. extends
A. The class that inherits properties and behaviors
B. The child class
C. The class that is inherited from
D. The class that is marked as "final"
In Java, can a subclass inherit constructors from its superclass?
A. Only if the subclass is marked as "final"
B. Yes, a subclass inherits constructors from its superclass
C. Only if the superclass is marked as "static"
D. Only if the subclass is marked as "final"
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