What is the output for the below code?
class A{
private void printName(){
System.out.println("Value-A");
}
}
class B extends A{
public void printName(){
System.out.println("Name-B");
}
}
public class Test{
public static void main (String[] args){
B b = new B();
b.printName();
}
}
class A{
private void printName(){
System.out.println("Value-A");
}
}
class B extends A{
public void printName(){
System.out.println("Name-B");
}
}
public class Test{
public static void main (String[] args){
B b = new B();
b.printName();
}
}A. Value-A
B. Name-B
C. Value-A Name-B
D. Compilation fails - private methods can't be override
E. None of these
Answer: Option B
Solution(By Examveda Team)
You can not override private method , private method is not availabe in subclass . In this case printName() method a class A is not overriding by printName() method of class B. printName() method of class B different method. So you can call printName() method of class B.
This Question Belongs to Java Program >> Overriding And Overloading
What is method overriding in Java?
A. Redefining a superclass method in a subclass
B. Defining a new method with the same name in a subclass
C. Making a method private in a subclass
D. Hiding methods in a superclass
What is the purpose of method overloading in Java?
A. Creating static methods
B. Hiding methods in a superclass
C. Redefining methods in a subclass
D. Defining multiple methods with the same name but different parameters
A. @OverrideMethod
B. @OverrideSuper
C. @Override
D. @OverrideParent
What happens when a subclass tries to override a final method from the superclass in Java?
A. The final method is hidden
B. It results in a compilation error
C. The final method becomes static
D. The final method is hidden
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