What is the output of the following code?

#include<stdio.h>
int get_min(int a, int b)
{
     if(a<b)
        return a;
     return b;
}
int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n)
{
     int t1[n], t2[n], i;
     t1[0] = entry[0] + spent[0][0];
     t2[0] = entry[1] + spent[1][0];
     for(i = 1; i < n; i++)
     {
         t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]);
         t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i]);
     }
     return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}
int main()
{
    int time_to_reach[][3] = {{6, 1, 5},
                           {2, 4, 7}};
    int time_spent[][4] = {{6, 5, 4, 7},
                        {5, 10, 2, 6}};
    int entry_time[2] = {5, 6};
    int exit_time[2] = {8, 9};
    int num_of_stations = 4;
    int ans = minimum_time_required(time_to_reach, time_spent, 
              entry_time, exit_time, num_of_stations);
    printf("%d",ans);
    return 0;
}

A. 32

B. 33

C. 34

D. 35

Answer: Option C