What is the output of the following code?

#include<stdio.h>
int get_min(int a, int b)
{
      if(a<b)
        return a;
      return b;
}
int minimum_time_required(int reach[][4],int spent[][5], int *entry, int *exit, int n)
{
      int t1[n], t2[n], i;
      t1[0] = entry[0] + spent[0][0];
      t2[0] = entry[1] + spent[1][0];
      for(i = 1; i < n; i++)
      {
          t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]);
          t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i]);
      }
      return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}
int main()
{
     int time_to_reach[][4] = {{16, 10, 5, 12},
                           {12, 4, 17, 8}};
     int time_spent[][5] = {{13, 5, 20, 19, 9},
                        {15, 10, 12, 16, 13}};
     int entry_time[2] = {12, 9};
     int exit_time[2] = {10, 13};
     int num_of_stations = 5;
     int ans = minimum_time_required(time_to_reach, time_spent, 
               entry_time, exit_time, num_of_stations);
     printf("%d",ans);
     return 0;
}

A. 62

B. 69

C. 75

D. 88

Answer: Option D