What is the output of the following code: cout << (5 != 5); in C++?

Solution (By Examveda Team)

This question asks us to find the output of a simple C++ code snippet.
The `cout` part is used to print something to the screen in C++.
Inside `cout`, we have the expression `(5 != 5)`. Let's break this down.
The `!=` is an "inequality operator". It means "not equal to".
This operator checks if the value on its left side is NOT equal to the value on its right side.
So, `5 != 5` is asking: "Is 5 not equal to 5?"
Let's evaluate this statement: Is 5 actually different from 5? No, 5 is exactly equal to 5.
Therefore, the statement `5 != 5` is false.
In C++, when you print a boolean value (true or false) directly using `cout` without any special formatting, it typically prints a numerical equivalent:
- `true` is usually printed as `1`.
- `false` is usually printed as `0`.
Since `5 != 5` evaluates to `false`, `cout` will print its numerical representation.
Thus, the final output will be 0.
The correct answer is Option D.