What is the output of the following code: int square(int x) { return x * x; } int main() { cout << square(3) + square(2); } in C++?
A. 13
B. 25
C. 12
D. Compilation error due to mismatched return types
Answer: Option A
Solution (By Examveda Team)
The given code defines a function namedsquare which takes an integer x as input and returns the square of x. In the main function, square(3) returns 9 and square(2) returns 4. When these values are added together and printed, the output will be 9 + 4 = 13.This Question Belongs to C Plus Plus Programming >> Functions And Procedures In C Plus Plus
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Comments (1)
What is the correct syntax for defining a function in C++?
A. returnType functionName(parameters) { body; }
B. functionName(parameters) { returnType body; }
C. functionName(returnType, parameters) { body; }
D. returnType functionName(parameters, body) { }
What is the purpose of a function prototype in C++?
A. Determines the parameters of the function
B. Specifies the return type of the function
C. Provides the implementation of the function
D. Declares the function before it is defined
Which keyword is used to define a function in C++ that does not return any value?
A. return
B. null
C. void
D. None of the above
What is the correct way to call a function named "add" that takes two parameters in C++?
A. add(a, b);
B. add(int a, int b);
C. functionName = add(a, b);
D. add.functionName(a, b);
The output of the given code snippet can be determined by evaluating the expression square(3) + square(2).
The square() function takes an integer argument x and returns the square of that integer.
Let's evaluate the expression:
square(3) returns the square of 3, which is 9.
square(2) returns the square of 2, which is 4.
Adding the results of square(3) and square(2) together: 9 + 4 = 13.
So, the output of the code will be: 13 Option No B