What is the output of the following code: int square(int x) { return x * x; } int main() { cout << square(3) + square(2); } in C++?
A. 13
B. 25
C. 12
D. Compilation error due to mismatched return types
Answer: Option A
Solution (By Examveda Team)
The given code defines a function namedsquare which takes an integer x as input and returns the square of x. In the main function, square(3) returns 9 and square(2) returns 4. When these values are added together and printed, the output will be 9 + 4 = 13.This Question Belongs to C Plus Plus Programming >> Functions And Procedures In C Plus Plus
The output of the given code snippet can be determined by evaluating the expression square(3) + square(2).
The square() function takes an integer argument x and returns the square of that integer.
Let's evaluate the expression:
square(3) returns the square of 3, which is 9.
square(2) returns the square of 2, which is 4.
Adding the results of square(3) and square(2) together: 9 + 4 = 13.
So, the output of the code will be: 13 Option No B