What is the output of the following program code?
public class Test{
public static void main(String args[]){
try{
int i;
return;
}
catch(Exception e){
System.out.print("inCatchBlock");
}
finally{
System.out.println("inFinallyBlock");
}
}
}
public class Test{
public static void main(String args[]){
try{
int i;
return;
}
catch(Exception e){
System.out.print("inCatchBlock");
}
finally{
System.out.println("inFinallyBlock");
}
}
}A. inCatchBlock
B. inCatchBlock inFinallyBlock
C. inFinallyBlock
D. The program will return without printing anything
Answer: Option C
This Question Belongs to Java Program >> Exceptions
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Comments ( 1 )
A. An error that occurs during runtime
B. An error that occurs during compilation
C. A warning issued by the compiler
D. A type of loop
What is the purpose of the "try" block in exception handling?
A. It catches exceptions and handles them
B. It specifies the exception type
C. It contains the code that might throw an exception
D. It specifies the exception message
In Java, can a method declare multiple exceptions using the "throws" keyword?
A. Only if the method is marked as "static"
B. Yes, a method can declare multiple exceptions separated by commas
C. Only if the exceptions are marked as "final"
D. Only if the method is marked as "static"
Here, no exception is occurring which we have to handle, that's why catch block isn't executing but we all know, whether an exception is caught or not, finally always executes, so all the statements inside of finally block occurs