What is the output of the given code?
string = gets.chomp
case string
when string = "a"
print "alphabet a"
when string = "b"
print "alphabet b"
when string = "c"
print "alphabet c"
else
print "some other alphabet"
end
string = gets.chomp
case string
when string = "a"
print "alphabet a"
when string = "b"
print "alphabet b"
when string = "c"
print "alphabet c"
else
print "some other alphabet"
endA. alphabet a
B. b
alphabet b
C. alphabet c
D. Syntax error
Answer: Option B
Related Questions on Control Structures in Ruby
In Ruby, what does the unless keyword do?
A. Executes code if condition is true
B. Executes code if condition is false
C. Breaks out of loop if condition is true
D. Executes code only once if condition is true
What is the purpose of the case statement in Ruby?
A. To define a class
B. To handle multiple conditions with one expression
C. To declare a variable
D. To perform mathematical calculations

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