What is the output of this program #include< stdio h> #include<

What is the output of this program #include< stdio h> #include<...

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What is the output of this program?

#include<stdio.h>
#include<stdlib.h>
#include<fcntl.h>
 
int main()
{
    int fd, new_fd;
    char *buff;
    buff = (char *)malloc(sizeof(char)*8);
    fd = open("test.c",O_RDONLY);
    new_fd = dup(fd);
    close(fd);
    read(new_fd,buff,8);
    printf("%s\n",buff);
}

A. this program will not print anything

B. this program will print "#include"

C. this program will give the segmentation fault

D. this program will give the syntax error

Answer: Option B

This Question Belongs to Computer Science >> Linux

What is the output of this program?

`#include<stdio.h> #include<stdlib.h> #include<fcntl.h> int main() { int fd, new_fd; char buff; buff = (char )malloc(sizeof(char)*8); fd = open("test.c",O_RDONLY); new_fd = dup(fd); close(fd); read(new_fd,buff,8); printf("%s\n",buff); }`

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What is the output of this program #include< stdio h> #include<...

What is the output of this program? #include<stdio.h> #include<stdlib.h> #include<fcntl.h> int main() { int fd, new_fd; char *buff; buff = (char *)malloc(sizeof(char)*8); fd = open("test.c",O_RDONLY); new_fd = dup(fd); close(fd); read(new_fd,buff,8); printf("%s\n",buff); }

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What is the output of this program?

`#include<stdio.h> #include<stdlib.h> #include<fcntl.h> int main() { int fd, new_fd; char buff; buff = (char )malloc(sizeof(char)*8); fd = open("test.c",O_RDONLY); new_fd = dup(fd); close(fd); read(new_fd,buff,8); printf("%s\n",buff); }`