What is the result of the following code snippet?
try {
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}
throw new NullPointerException();
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (NullPointerException e) {
System.out.println("NullPointerException!");
}
A. NullPointerException!
B. Compilation error
C. Runtime exception
D. Arithmetic Exception!
Answer: Option A
Solution(By Examveda Team)
In the given code snippet, a NullPointerException is explicitly thrown within the try block. When an exception is thrown, the Java runtime looks for a catch block that matches the type of the thrown exception.In this case, since a NullPointerException is thrown, the catch block specifically catching NullPointerException will be executed. Therefore, the output of the code will be "NullPointerException!".
Hence, Option A: NullPointerException! is the correct result of the code snippet.
This Question Belongs to Java Program >> Exceptions
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Comments ( 1 )
A. An error that occurs during runtime
B. An error that occurs during compilation
C. A warning issued by the compiler
D. A type of loop
What is the purpose of the "try" block in exception handling?
A. It catches exceptions and handles them
B. It specifies the exception type
C. It contains the code that might throw an exception
D. It specifies the exception message
In Java, can a method declare multiple exceptions using the "throws" keyword?
A. Only if the method is marked as "static"
B. Yes, a method can declare multiple exceptions separated by commas
C. Only if the exceptions are marked as "final"
D. Only if the method is marked as "static"
The Answer 'D' is wrong because we are throwing a specific unchecked exception and we are having multiple catch blocks so the exception is handled by NullpointerException Only and we get out put as NullPointerException!