What is the subnetwork address for a host with the IP address 200.10.5.68/28?
A. 200.10.5.56
B. 200.10.5.32
C. 200.10.5.64
D. 200.10.5.0
Answer: Option C
Solution(By Examveda Team)
Explanation:Step 1:
The given IP address is 200.10.5.68 with a subnet mask of /28.
Step 2:
Convert the subnet mask from its decimal representation to binary.
The subnet mask /28 corresponds to 255.255.255.240 in decimal, which is 11111111.11111111.11111111.11110000 in binary.
Step 3:
Perform a bitwise "AND" operation between the IP address and the subnet mask.
IP address: 200.10.5.68 -> 11001000.00001010.00000101.01000100Subnet mask: 255.255.255.240 -> 11111111.11111111.11111111.11110000Subnet (AND): 200.10.5.64 -> 11001000.00001010.00000101.01000000Step 4:
The result of the "AND" operation is the subnetwork address.
Therefore, the subnetwork address for the host with the IP address 200.10.5.68/28 is:
C. 200.10.5.64
This output corresponds to the subnetwork address obtained by applying the subnet mask to the given IP address.
This Question Belongs to Networking >> Subnetting
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I need an explanation right now pleas
I fail to understand how to get 240 on last octet of the subnet mask.according to the question I asked initially
255.255.255.240
The given IP address was 200.10.68/28
(1). whats the next host address: 160. 16. 208. 118/22
(2). how would you find the new network address,
broadcast address and subnet mask: 123. 0. 0. 0/26
(1). whats the next host address: 160. 16. 208. 118/22
(2). how do you find the next host address, broadcast address
and subnet mask: 123. 0. 0.0/26
Hi, why answer c is not correct as the 4th octet contains 32. only 64 is correct why?? The answer will be B&C both ???