What is the time complexity of the following dynamic programming algorithm used to find the maximum sub-array sum?
#include<stdio.h>
int max_num(int a,int b)
{
if(a> b)
return a;
return b;
}
int maximum_subarray_sum(int *arr, int len)
{
int sum[len], idx;
sum[0] = arr[0];
for(idx = 1; idx < len; idx++)
sum[idx] = max_num(sum[idx - 1] + arr[idx], arr[idx]);
int mx = sum[0];
for(idx = 0; idx < len; idx++)
if(sum[idx] > mx)
mx =sum[idx];
return mx;
}
int main()
{
int arr[] = {-2, -5, 6, -2, 3, -1, 0,-5, 6}, len = 9;
int ans = maximum_subarray_sum(arr, len);
printf("%d",ans);
return 0;
}
#include<stdio.h>
int max_num(int a,int b)
{
if(a> b)
return a;
return b;
}
int maximum_subarray_sum(int *arr, int len)
{
int sum[len], idx;
sum[0] = arr[0];
for(idx = 1; idx < len; idx++)
sum[idx] = max_num(sum[idx - 1] + arr[idx], arr[idx]);
int mx = sum[0];
for(idx = 0; idx < len; idx++)
if(sum[idx] > mx)
mx =sum[idx];
return mx;
}
int main()
{
int arr[] = {-2, -5, 6, -2, 3, -1, 0,-5, 6}, len = 9;
int ans = maximum_subarray_sum(arr, len);
printf("%d",ans);
return 0;
}A. O(n)
B. O(logn)
C. O(nlogn)
D. O(n2)
Answer: Option A

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