What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8 distinct girlfriends such that each of them gets at least one gift?
A. 72 × 8!
B. 144 × 8!
C. 36 × 8!
D. 9!
Answer: Option C
Solution(By Examveda Team)
One among 8 gfs will get 2 gifts and remaining 7 will get one. So total of 9 gifts will be distributed among 8 gfs. i.e; 11111112 Gf who will get 2 gifts can be find out in 8C1 ways = 8 ways. Now 2 gifts can be given to selected gf in 9C2 ways. And remaining 7 gifts can be given to remaining 7 gf in 7! ways. So total no of ways= 8 × 9C2 × 7! = $$\frac{{8 \times \left( {9 \times 8} \right)}}{{2 \times 7!}}$$ = 36 × 8 × 7! = 36 × 8!Join The Discussion
Comments ( 2 )
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
That was an error. Corrected Now.
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