What will be the final values of a and c in the following C statement? (Initial values: a = 2, c = 1)
c = (c) ? a = 0 : 2;
c = (c) ? a = 0 : 2;A. a = 0, c = 0;
B. a = 2, c = 1;
C. a = 2, c = 2;
D. a = 1, c = 2;
Answer: Option A
Solution (By Examveda Team)
Initial values: a = 2, c = 1;The statement is:
c = (c) ? a = 0 : 2;This is a ternary conditional expression. The condition is (c), which means if c is non-zero, the expression before the colon is executed.
Since c = 1 (non-zero), the true part is executed: a = 0
Then the value of the true expression (a = 0) is assigned to c.
So now:
a becomes 0
c becomes 0 (since the result of a = 0 is 0)
Final values: a = 0, c = 0
This Question Belongs to C Program >> C Fundamentals
Step-by-step explanation:
This uses the ternary operator:
c
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condition ? expr_if_true : expr_if_false;
So we evaluate:
c is currently 1 → which is true (non-zero in C).
Therefore, the true part is executed:
c
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a = 0
and this assignment expression returns the value 0.
So the full statement becomes:
c
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c = a = 0; // a becomes 0, and c is assigned that same value
✅ Final values:
a = 0
c = 0
✅ Answer:
a = 0, c = 0
It should be because
c = (c) ? a = 0 : 2; // a = 0 will become c's value as (c) is true since it has a non zero value
next step will be
c = a = 0; // in this one, c is also defined as 0