What will be the final values of i and j in the following C code?

#include <stdio.h>
int x = 0;
int f()
{
    if (x == 0)
        return x + 1;
    else
        return x - 1;
}
int g()
{
    return x++;
}
int main()
{
    int i = (f() + g()) | g(); //bitwise or
    int j = g() | (f() + g()); //bitwise or
}