What will be the output for the following code?

#include <stdio.h> 
void combination(int arr[], int aux[], int start, int end, int index, int r); 
void print(int arr[], int n, int r) 
{ 	
	int aux[r]; 
        combination(arr, aux, 0, n-1, 0, r); 
}
void combination(int arr[], int aux[], int start, int end, int index, int r) 
{ 	
	if (index == r) 
	{ 
		for (int j=0; j<r; j++) 
			printf("%d ", aux[j]); 
		printf(", "); 
		return; 
	} 	
	for (int i=start; i<=end && end-i+1 >= r-index; i++) 
	{   aux[index] = arr[i]; 
		combination(arr, aux, i+1, end, index+1, r); 
	} 
}  
int main() 
{ 
	int arr[] = {1, 2, 3}; 
	int r = 2; 
	int n = sizeof(arr)/sizeof(arr[0]); 
	print(arr, n, r); 
}

A. 1 2, 1 3, 2 3

B. 1 3,1 2,2 3,

C. 1 2, 1 3, 2 3,

D. 1 2,1 3,2 3,

Answer: Option C