What will be the output for the following code?

#include<stdio.h> 
void combination(int arr[],int n,int r,int index,int aux[],int i); 
void print(int arr[], int n, int r) 
{ 	
	int aux[r]; 
	combination(arr, n, r, 0, aux, 0); 
} 
void combination(int arr[], int n, int r, int index, int aux[], int i) 
{ 	
	if (index == r) 
	{ 
		for (int j=0; j<r; j++) 
			printf("%d ",aux[j]); 
		printf(", "); 
		return; 
	} 
	if (i >= n) 
		return; 
	aux[index] = arr[i]; 
	combination(arr, n, r, index+1, aux, i+1); 
	combination(arr, n, r, index, aux, i+1); 
} 
int main() 
{ 
	int arr[] = {1, 2,2}; 
	int r = 2; 
	int n = sizeof(arr)/sizeof(arr[0]); 
	print(arr, n, r); 
	return 0; 
}

A. 1 2, 1 2, 2 2

B. 1 2, 1 2, 2 2 ,

C. 1 2, 2 1, 2 2 ,

D. 1 2, 2 1, 2 2

Answer: Option B