What will be the output of the following C code?
#include <stdio.h>
int main()
{
int a[5] = {1, 2, 3, 4, 5};
int i;
for (i = 0; i < 5; i++)
if ((char)a[i] == '5')
printf("%d\n", a[i]);
else
printf("FAIL\n");
}
#include <stdio.h>
int main()
{
int a[5] = {1, 2, 3, 4, 5};
int i;
for (i = 0; i < 5; i++)
if ((char)a[i] == '5')
printf("%d\n", a[i]);
else
printf("FAIL\n");
}A. The compiler will flag an error
B. The program will compile and print the output 5
C. The program will compile and print the ASCII value of 5
D. The program will compile and print FAIL for 5 times
Answer: Option D
This Question Belongs to C Program >> C Fundamentals
Related Questions on C Fundamentals
What is the primary purpose of a function prototype in C?
A. Declare a variable
B. Declare a function
C. Define a function
D. Assign a value
What is the correct syntax for declaring a variable in C?
A. int variable_name;
B. variable_name = 5;
C. variable_name int;
D. int = variable_name;
Join The Discussion