What will be the output of the following C code?
#include <stdio.h>
int main()
{
int x = 2, y = 0;
int z = (y++) ? y == 1 && x : 0;
printf("%d\n", z);
return 0;
}
#include <stdio.h>
int main()
{
int x = 2, y = 0;
int z = (y++) ? y == 1 && x : 0;
printf("%d\n", z);
return 0;
}
A. 0
B. 1
C. Undefined behaviour
D. Compile time error
Answer: Option A
Related Questions on C Fundamentals
What is the primary purpose of a function prototype in C?
A. Declare a variable
B. Declare a function
C. Define a function
D. Assign a value
What is the correct syntax for declaring a variable in C?
A. int variable_name;
B. variable_name = 5;
C. variable_name int;
D. int = variable_name;
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