What will be the output of the following C code?
#include <stdio.h>
int main()
{
char c;
int i = 0;
FILE *file;
file = fopen("test.txt", "w+");
fprintf(file, "%c", 'a');
fprintf(file, "%c", -1);
fprintf(file, "%c", 'b');
fclose(file);
file = fopen("test.txt", "r");
while ((c = fgetc(file)) != -1)
printf("%c", c);
return 0;
}
#include <stdio.h>
int main()
{
char c;
int i = 0;
FILE *file;
file = fopen("test.txt", "w+");
fprintf(file, "%c", 'a');
fprintf(file, "%c", -1);
fprintf(file, "%c", 'b');
fclose(file);
file = fopen("test.txt", "r");
while ((c = fgetc(file)) != -1)
printf("%c", c);
return 0;
}A. a
B. Infinite loop
C. Depends on what fgetc returns
D. Depends on the compiler
Answer: Option A
Related Questions on C Fundamentals
What is the primary purpose of a function prototype in C?
A. Declare a variable
B. Declare a function
C. Define a function
D. Assign a value
What is the correct syntax for declaring a variable in C?
A. int variable_name;
B. variable_name = 5;
C. variable_name int;
D. int = variable_name;

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