What will be the output of the following C code?
#include <stdio.h>
void main()
{
double b = 3 % 0 * 1 - 4 / 2;
printf("%lf", b);
}
#include <stdio.h>
void main()
{
double b = 3 % 0 * 1 - 4 / 2;
printf("%lf", b);
}A. -2
B. Floating point Exception
C. 1
D. 0
Answer: Option B
This Question Belongs to C Program >> C Fundamentals
Related Questions on C Fundamentals
What is the primary purpose of a function prototype in C?
A. Declare a variable
B. Declare a function
C. Define a function
D. Assign a value
What is the correct syntax for declaring a variable in C?
A. int variable_name;
B. variable_name = 5;
C. variable_name int;
D. int = variable_name;
Join The Discussion