What will be the output of the following C code?
#include <stdio.h>
int main()
{
int y = 0;
if (1 |(y = 1))
printf("y is %d\n", y);
else
printf("%d\n", y);
}
#include <stdio.h>
int main()
{
int y = 0;
if (1 |(y = 1))
printf("y is %d\n", y);
else
printf("%d\n", y);
}
A. y is 1
B. 1
C. run time error
D. undefined
Answer: Option A
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