What will be the output of the following C code?
#include <stdio.h>
int foo(int, int);
#define foo(x, y) x / y + x
int main()
{
int i = -6, j = 3;
printf("%d ",foo(i + j, 3));
#undef foo
printf("%d\n",foo(i + j, 3));
}
int foo(int x, int y)
{
return x / y + x;
}
#include <stdio.h>
int foo(int, int);
#define foo(x, y) x / y + x
int main()
{
int i = -6, j = 3;
printf("%d ",foo(i + j, 3));
#undef foo
printf("%d\n",foo(i + j, 3));
}
int foo(int x, int y)
{
return x / y + x;
}A. -8 -4
B. Compile time error
C. -8 -8
D. Undefined behaviour
Answer: Option A
Related Questions on Function
In C, what is a function primarily used for?
A. Decision making
B. Variable declaration
C. Code organization and reusability
D. Printing output
What is the purpose of a function prototype in C?
A. To declare a function's return type
B. To declare a function's name
C. To declare a function's parameters and return type
D. To declare a function's name and parameters
In C, how are function arguments passed by default?
A. By value
B. By reference
C. By pointer
D. By address
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