What will be the output of the following C code?
#include <stdio.h>
int i;
int main()
{
extern int i;
if (i == 0)
printf("scope rules\n");
}
#include <stdio.h>
int i;
int main()
{
extern int i;
if (i == 0)
printf("scope rules\n");
}A. scope rules
B. Compile time error due to multiple declaration
C. Compile time error due to not defining type in statement extern i
D. Nothing will be printed as value of i is not zero because i is an automatic variable
Answer: Option A
Related Questions on Function
In C, what is a function primarily used for?
A. Decision making
B. Variable declaration
C. Code organization and reusability
D. Printing output
What is the purpose of a function prototype in C?
A. To declare a function's return type
B. To declare a function's name
C. To declare a function's parameters and return type
D. To declare a function's name and parameters
In C, how are function arguments passed by default?
A. By value
B. By reference
C. By pointer
D. By address
Join The Discussion