What will be the output of the following C code #include...

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Pointer

What will be the output of the following C code?

#include <stdio.h>
int add(int a, int b)
{
    return a + b;
}
int main()
{
    int (*fn_ptr)(int, int);
    fn_ptr = add;
    printf("The sum of two numbers is: %d", (int)fn_ptr(2, 3));
}

A) Compile time error, declaration of a function inside main B) Compile time error, no definition of function fn_ptr C) Compile time error, illegal application of statement fn_ptr = add D) No Run time error, output is 5

Answer & Solution

Correct Answer: Option D

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What will be the output of the following C code #include...

What will be the output of the following C code? #include <stdio.h> int add(int a, int b) { return a + b; } int main() { int (*fn_ptr)(int, int); fn_ptr = add; printf("The sum of two numbers is: %d", (int)fn_ptr(2, 3)); }

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What will be the output of the following C code?

`#include <stdio.h> int add(int a, int b) { return a + b; } int main() { int (*fn_ptr)(int, int); fn_ptr = add; printf("The sum of two numbers is: %d", (int)fn_ptr(2, 3)); }`