What will be the output of the following C code?
#include <stdio.h>
int main()
{
void *p;
int a[4] = {1, 2, 3, 8};
p = &a[3];
int *ptr = &a[2];
int n = p - ptr;
printf("%d\n", n);
}
#include <stdio.h>
int main()
{
void *p;
int a[4] = {1, 2, 3, 8};
p = &a[3];
int *ptr = &a[2];
int n = p - ptr;
printf("%d\n", n);
}A. 1
B. Compile time error
C. Segmentation fault
D. 4
Answer: Option B
Related Questions on Pointer
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A. Decision making
B. Code organization
C. Variable declaration
D. Storing values
In C, how do you declare a pointer variable that can store the address of an integer?
A. int *ptr;
B. ptr int;
C. int ptr;
D. ptr *int;
What is the purpose of the '->' operator in C when used with pointers?
A. Arithmetic operation
B. Indirection operator
C. Member access operator
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