What will be the output of the following C code?
#include <stdio.h>
int main()
{
foo(ary);
}
void foo(int **ary)
{
int i = 10, k = 20, j = 30;
int *ary[2];
ary[0] = &i;
ary[1] = &j;
printf("%d\n", ary[0][1]);
}
#include <stdio.h>
int main()
{
foo(ary);
}
void foo(int **ary)
{
int i = 10, k = 20, j = 30;
int *ary[2];
ary[0] = &i;
ary[1] = &j;
printf("%d\n", ary[0][1]);
}A. 10
B. 20
C. Compile time error
D. Undefined behaviour
Answer: Option D
Related Questions on Pointer
In C, what is a pointer primarily used for?
A. Decision making
B. Code organization
C. Variable declaration
D. Storing values
In C, how do you declare a pointer variable that can store the address of an integer?
A. int *ptr;
B. ptr int;
C. int ptr;
D. ptr *int;
What is the purpose of the '->' operator in C when used with pointers?
A. Arithmetic operation
B. Indirection operator
C. Member access operator
D. Bitwise operation
Join The Discussion