What will be the output of the following C code?
#include <stdio.h>
struct p
{
char *name;
struct p *next;
};
struct p *ptrary[10];
int main()
{
struct p p, q;
p.name = "xyz";
p.next = NULL;
ptrary[0] = &p;
strcpy(q.name, p.name);
ptrary[1] = &q;
printf("%s\n", ptrary[1]->name);
return 0;
}
#include <stdio.h>
struct p
{
char *name;
struct p *next;
};
struct p *ptrary[10];
int main()
{
struct p p, q;
p.name = "xyz";
p.next = NULL;
ptrary[0] = &p;
strcpy(q.name, p.name);
ptrary[1] = &q;
printf("%s\n", ptrary[1]->name);
return 0;
}A. Compile time error
B. Segmentation fault/code crash
C. Depends on the compiler
D. xyz
Answer: Option B
Solution (By Examveda Team)
In this code, the variableq is declared but not initialized. When you try to use strcpy function to copy the value of p.name to q.name, you are accessing memory that has not been allocated for q.name, which leads to undefined behavior. This undefined behavior could result in a segmentation fault or a code crash. Therefore, the correct answer is Option B: Segmentation fault/code crash.
This Question Belongs to C Program >> Structure And Union
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