What will be the output of the following C code (run without any command line arguments)?
#include <stdio.h>
int main(int argc, char *argv[])
{
while (*argv != NULL)
printf("%s\n", *(argv++));
return 0;
}
#include <stdio.h>
int main(int argc, char *argv[])
{
while (*argv != NULL)
printf("%s\n", *(argv++));
return 0;
}A. Segmentation fault/code crash
B. Executable file name
C. Depends on the platform
D. Depends on the compiler
Answer: Option B
Related Questions on Pointer
In C, what is a pointer primarily used for?
A. Decision making
B. Code organization
C. Variable declaration
D. Storing values
In C, how do you declare a pointer variable that can store the address of an integer?
A. int *ptr;
B. ptr int;
C. int ptr;
D. ptr *int;
What is the purpose of the '->' operator in C when used with pointers?
A. Arithmetic operation
B. Indirection operator
C. Member access operator
D. Bitwise operation
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