What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int f(int &x, int c)
{
c = c - 1;
if (c == 0) return 1;
x = x + 1;
return f(x, c) * x;
}
int main(int argc, char const *argv[])
{
int a = 4;
cout<<f(a,a);
return 0;
}
#include <iostream>
using namespace std;
int f(int &x, int c)
{
c = c - 1;
if (c == 0) return 1;
x = x + 1;
return f(x, c) * x;
}
int main(int argc, char const *argv[])
{
int a = 4;
cout<<f(a,a);
return 0;
}A. 343
B. 336
C. 120
D. 840
Answer: Option A
Related Questions on Pointers and References in C plus plus
A. A variable that stores the size of another variable
B. A variable that stores the address of another variable
C. A variable that stores a reference to another variable
D. None of the above
What is the output of the following code: int x = 5; int *ptr = &x; cout << *ptr; in C++?
A. Address of x
B. Garbage value
C. Compilation error
D. 5

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