What will be the output of the following C++ code?
#include <iostream>
#include <functional>
#include <numeric>
using namespace std;
int myop (int x, int y)
{
return x + y;
}
int main ()
{
int val[] = {1, 2, 3, 5};
int result[7];
adjacent_difference (val, val + 7, result);
for (int i = 0; i < 4; i++)
cout << result[i] <<' ';
return 0;
}
#include <iostream>
#include <functional>
#include <numeric>
using namespace std;
int myop (int x, int y)
{
return x + y;
}
int main ()
{
int val[] = {1, 2, 3, 5};
int result[7];
adjacent_difference (val, val + 7, result);
for (int i = 0; i < 4; i++)
cout << result[i] <<' ';
return 0;
}A. 1 1 1 2
B. 1 2 3 1
C. 1 2 3 5
D. 1 2 5 6
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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