What will be the output of the following C++ code?
#include<iostream>
using namespace std;
class X
{
int m;
public:
X() : m(10)
{
}
X(int mm): m(mm)
{
}
int getm()
{
return m;
}
};
class Y : public X
{
int n;
public:
Y(int nn) : n(nn) {}
int getn() { return n; }
};
int main()
{
Y yobj( 100 );
cout << yobj.getm() << " " << yobj.getn() << endl;
}
#include<iostream>
using namespace std;
class X
{
int m;
public:
X() : m(10)
{
}
X(int mm): m(mm)
{
}
int getm()
{
return m;
}
};
class Y : public X
{
int n;
public:
Y(int nn) : n(nn) {}
int getn() { return n; }
};
int main()
{
Y yobj( 100 );
cout << yobj.getm() << " " << yobj.getn() << endl;
}A. 10 100
B. 100 10
C. 10 10
D. 100 100
Answer: Option A
This Question Belongs to C Plus Plus Programming >> C Plus Plus Miscellaneous
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it
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