What will be the output of the following C++ code?
#include <iostream>
using namespace std;
class poly
{
protected:
int width, height;
public:
void set_values(int a, int b)
{
width = a; height = b;
}
};
class Coutput
{
public:
void output(int i);
};
void Coutput::output(int i)
{
cout << i;
}
class rect:public poly, public Coutput
{
public:
int area()
{
return(width * height);
}
};
class tri:public poly, public Coutput
{
public:
int area()
{
return(width * height / 2);
}
};
int main()
{
rect rect;
tri trgl;
rect.set_values(3, 4);
trgl.set_values(4, 5);
rect.output(rect.area());
trgl.output(trgl.area());
return 0;
}
#include <iostream>
using namespace std;
class poly
{
protected:
int width, height;
public:
void set_values(int a, int b)
{
width = a; height = b;
}
};
class Coutput
{
public:
void output(int i);
};
void Coutput::output(int i)
{
cout << i;
}
class rect:public poly, public Coutput
{
public:
int area()
{
return(width * height);
}
};
class tri:public poly, public Coutput
{
public:
int area()
{
return(width * height / 2);
}
};
int main()
{
rect rect;
tri trgl;
rect.set_values(3, 4);
trgl.set_values(4, 5);
rect.output(rect.area());
trgl.output(trgl.area());
return 0;
}A. 1212
B. 1210
C. 1010
D. 1250
Answer: Option B
What does the 'sizeof' operator return in C++?
A. Size of a data type in bits
B. Size of a data type in bytes
C. Size of a variable in bytes
D. Size of a variable in bits
What is the purpose of the 'static' keyword in C++?
A. To declare a variable with dynamic storage duration
B. To declare a constant
C. To declare a variable with external linkage
D. To declare a variable with static storage duration
What is the difference between '++i' and 'i++' in C++?
A. None of the above
B. They both have the same effect
C. '++i' increments the value of 'i' before returning it, while 'i++' increments the value of 'i' after returning it
D. '++i' increments the value of 'i' after returning it, while 'i++' increments the value of 'i' before returning it

Join The Discussion